Do any one question frow these three
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shamsadhussainp9dq4j:
first will be √64= 8
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hey these are the answers
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good thought that you have written
hi dahiya & pragya sharma
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keep questioning I will help you in telling your answers
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2
First bit
Answer a) 8
b) 2
c)5
Second bit
Answer a) 27
b)4
c)8
d)625(maybe cuz I can't see the last part)
In this problems,you have to find the powers like if it is for example 1at one 64^1/2,then you have to find the square root of 64 which is 8. And the if u square the root number 8,u should get 64. So after you fins root of the actual no.you have to keep 8^2 so that on the power 1/2 cancels and you'll remain with 8 as the answer.
But like in 2nd bit you've 9^3/2,so first u have to check the denominator of the power first. So root of 9 is 3. So keep (3^2)3/2. So now 2 cancels an snow you r left with 3^3.find the cube of 3 which is 27..
Hope this helps you.
Answer a) 8
b) 2
c)5
Second bit
Answer a) 27
b)4
c)8
d)625(maybe cuz I can't see the last part)
In this problems,you have to find the powers like if it is for example 1at one 64^1/2,then you have to find the square root of 64 which is 8. And the if u square the root number 8,u should get 64. So after you fins root of the actual no.you have to keep 8^2 so that on the power 1/2 cancels and you'll remain with 8 as the answer.
But like in 2nd bit you've 9^3/2,so first u have to check the denominator of the power first. So root of 9 is 3. So keep (3^2)3/2. So now 2 cancels an snow you r left with 3^3.find the cube of 3 which is 27..
Hope this helps you.
thanks
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