Question

A train starting from rest moves with a uniform acceleration of 5m/s² for 5 minutes. Calculate 1) The speed acquired 2) Distance travelled​

Answer 1

Initial velocity, u=0m/s

Final velocity, yv=?

Acceleration, a=0.2m/s

2

Time, t=5min=5×60=300sec

Using first equation of motion to obtain the final speed:

v=u+at

v=0+0.2×300=60m/s

And the distance travelled is

s=ut+

2

1

αt

2

s=0×300+

2

1

×0.2×300×300

s=0+9000=9000m=9km

Answer 2

Initial velocity, u=0m/s
Final velocity, yv=?
Acceleration, a=0.2m/s
2

Time, t=5min=5×60=300sec

Using first equation of motion to obtain the final speed:
v=u+at
v=0+0.2×300=60m/s

And the distance travelled is
s=ut+
2
1
​
αt
2


s=0×300+
2
1
​
×0.2×300×300

s=0+9000=9000m=