Question

A train starting from rest moves with uniform acceleration of 0.2 m/s2 for 5 minutes. Calculate the final velocity and the distance travelled during this time.

Answer 1

Answer:

u = 0 m/s

a= 0.2 m/s²

t= 5 ×60 sec = 300 sec

v= 0+2/10× 300

=60 m/ s

s= 0*300 + (2/10*300*300)/2

= 9000

Answer 2

Answer:

final velocity(v)= 60 m/s

Explanation:

given are: acceleration= 0.2 m/s2

                 initial velocity= 0 m/s

                 time = 5 min

first we should convert 5 min to sec so, we should multiply by 60

5* 60= 300 sec

now we know that, a = v-u/t

therefore, 0.2 m/s2 = v-0/300

now, v-0= 300*0.2= 60

so, v= 60 + 0 = 60 m/s