Question

A train starting from rest moves with uniform acceleration of 0.2 m per secsquare for 5 min. Calculate the speed acquired and the distance travelled in this time

Answer 1

Answer:

Explanation:

u (initial Velocity)= 0 m / s

Acceleration a = 0.2 m / s²

time=300s

v=u+at

=0+0.2*300=60m/s

v²=u²+2as

60²=0+2*0.2*s

3600=0.4*s

S=3600*10/0.4*10=9000m

Speed/Velocity=60m/s

Distance=9000m