Question

A train starting from stationary position and moving uniform acceleration attains a speed of 36km/hr in 10 min. Find its acceleration

Answer 1

Initial velocity(u) = 0 m/s
Final velocity(v) =36 km/hr or 10 m/s
Time(t) =10 min or 600 sec

We know,
Equation of motion:

v=u+at

Putting values:
10=a(600)
a =10/600
a =0.16 m/s²

∴ Acceleration = 0.16 m/s² ← (Answer)

Good Studies!