A train starting from stationary position and moving uniform acceleration attains a speed of 36km/hr in 10 min. Find its acceleration
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Initial velocity(u) = 0 m/s
Final velocity(v) =36 km/hr or 10 m/s
Time(t) =10 min or 600 sec
We know,
Equation of motion:
v=u+at
Putting values:
10=a(600)
a =10/600
a =0.16 m/s²
∴ Acceleration = 0.16 m/s² ← (Answer)
Good Studies!
Final velocity(v) =36 km/hr or 10 m/s
Time(t) =10 min or 600 sec
We know,
Equation of motion:
v=u+at
Putting values:
10=a(600)
a =10/600
a =0.16 m/s²
∴ Acceleration = 0.16 m/s² ← (Answer)
Good Studies!
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