A train starting from stationary position and moving with uniform accelaration attains a speed of 36km/hour in 10 minutes.what is the distance travelled?
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initial velocity(u)=0 m/s
final velocity(v)=36 km/hr=10 m/s
time(t)=10 min=600s
so,a=(v-u)/t=(10-0)/600=1/60 m/s^2
s=ut+1/2at^2
s=1/2 x 1/60 x 3600
s=30 m.
final velocity(v)=36 km/hr=10 m/s
time(t)=10 min=600s
so,a=(v-u)/t=(10-0)/600=1/60 m/s^2
s=ut+1/2at^2
s=1/2 x 1/60 x 3600
s=30 m.
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◆Ekansh Nimbalkar◆
hello friend here is your required answer
hello friend here is your required answer
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