Question

a train starting from stationary position and moving with uniform acceleration attains the speed of 36 km hr in 10 min. find acceleration

Answer 1

Initial velocity=0m/s
Final velocity=36km/h=10m/s
Time =10min =600sec
A=(v-u)/t
A=(36-0)/600
=36/600
=0.06m/s^2

Answer 2

Answer:

initial velocity, u = 0 m/s. (as the train starts from rest)

final velocity, v = 36 km/h = 36×5÷18 = 10 m/s

time taken, t = 10 min = 60×10 = 600s

Explanation:

We know that:

acceleration = final velocity - initial velocity/ time taken

a = v-u/ t

= 10-0/ 600

a = 0.01 m/s^2