Question

A train starting from stationary position moving with uniform accelaration attains a speed of 36m/second in 10 minute?Find it Acceleration?
<ONLY CLEVER CAN ANSWER IT>

Answer 1

Acceleration=(final velocity-initial velocity)/time[i.e.,rate of change of velocity]
                    =36-0/(10*60)
                    =36/600
                    =0.06 m/s^2
                                   (Or)
from first equation of motion,
   v=u+at
  36=0+a(600)
    a=36/600
    a=0.06 m/s^2

Answer 2

v=36m/sec
t=10min
u=o
v=u+at
36=10a
a=3.6m/s²