Question

A train starts from a certain station with speed of 105 km/hr., after travelling 7 hrs. train get accident and speed of train decreases by 30 km/hr. and train will late by 4 hours 48 minutes. Find the total distance of journey.
)1512 km b)2205 km c)1890 km d)1995 km
Plz solve this

Answer 1

Answer:

The correct option is d) 1995

Step-by-step explanation:

Given,

Original speed = 105 km/h,

Time in first part of the journey = 7 hours,

∵ Distance = speed × time,

So, the distance covered in first part of the journey = 105 × 7 = 735 km,

Now, speed in second part of the journey = 105 km/h - 30 km/h = 75 km/h,

Let x be the number of hours spend in second part of the journey,

Then the distance covered in second part = 75x,

Thus, the total distance = 735 + 75x,

Now, according to the question,

If the speed is 105 km/h in entire journey,

Time = ( x + 7 - $4\frac{48}{60}$ ) hours

$= x + 7 - 4\frac{4}{5}$

Thus, the total distance = $105\times (x + 7 - 4\frac{4}{5})$

$\implies 735 + 75x = 105(x + 7 - \frac{24}{5})$

$735 + 75x = 105(x + \frac{35 - 24}{5})$

$735 + 75x = 105(x +\frac{11}{5})$

$735 + 75x = 105x + 231$

$735 - 231 = 105x - 75x$

$504 =30x$

$\implies x =\frac{504}{30}=16.8$

Hence, the total distance of the journey = 735 + 75(16.8)

= 735 + 1260

= 1995 km,

Learn more :

A train was late by 6 min. the driver increased its speed by 4 km/hr. at the next station, 36 km away, the train reached on time. find the original speed of the train?

https://brainly.in/question/3516737

Answer 2

Answer:

speed= 105:75

7:5

time=. 5:7

diff 2-24/5

5---12hr

total time 12+7=19

distance =s×t=105×19=1995