A train starts from a station and moves with a constant acceleration for 2 minutes . If it covers a distance of 400 m in this period, find the acceleration .
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u=0 m/s
t=2 minutes=2×60=120 seconds
s=400 m
s=ut+1/2at^2
400=0(120)+0.5×a×(120)^2
400=0+0.5a×14400
400=7200a
400÷7200=a
1÷8=a
0.125 m/s^2=a
t=2 minutes=2×60=120 seconds
s=400 m
s=ut+1/2at^2
400=0(120)+0.5×a×(120)^2
400=0+0.5a×14400
400=7200a
400÷7200=a
1÷8=a
0.125 m/s^2=a
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