Question

A train starts from rest and accelerates uniformly at the rate of 5m/s^2 for 5sec. Calculate the velocity of train in 5sec

Answer 1

Initial velocity (u) =0
Time taken (t) = 5s
acceleration of the train (a) =5ms^-2
Let the final velocity be v ms^-1
Now, Since. , a = (v-u)/t
→ 5 = v -0/5
→v =25
Thus, final velocity of the object =25ms^-1

Answer 2

Answer:

Hi there!!

we can use this formula v=u+at

initial velocity (u) = 0

acceleration = 5m/s^2

time taken= 5 seconds

v=u+at

v=0+5×5

v=25m/s

Explanation:

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