Question

A train starts from rest and accelerates uniformly for 30s to acquire a velocity of 108 km/h. It travels with this velocity for 20 min. The driver now applies brakes and the train retards uniformly to stop after 20s. Find the total distance covered by the train.​

Answer 1

Explanation:

U=0 t=30 v= 30

v = u +at

30 = a 30

a=1 m/s

s = ut +1/2 at ^2

= 30 *15

= 450 m

now ,

20 ×60

1200 is your answer buddy

PLSS MARK AS A BRAINLIEST

Answer 2

Answer:

$36750 \: m$

Explanation:

When the train starts from rest,

u= 0,

t= 30s,

v= 108 km/h = 108 × 5/18 = 30 m/s.

Now,

a= v-u/t = 1 m/s².

Distance ,S1 = ut + 1/2 at²

= 0 + 1/2 × 1 × 30 × 30

= 450 m.

At uniform velocity of 30 m/s for 20 min, i.e., 1200s,

Distance, S2 = 30 × 1200 = 36000 m.

Now,

On applying brakes,

t= 20s,

u= 30 m/s,

v= 0.

a= v-u/t = 0-30/20 = -1.5 m/s²

Distance S3 = v² - u²/2a

= 0 - (30)² /2 × 1.5

= 300 m

Therefore,

The total distance traversed = S1 + S2 + S3

= (450 + 36000 + 300) m

= 36750 m