Question

a train starts from rest and acceleration uniformly at the rate of 5m/s2 for 5 sec calculate the velocity of the train in 5 sec

Answer 1

ProvidEd that:

• Initial velocity = 0 m/s
• Acceleration = 5 m/s sq.
• Time = 5 seconds
• Final velocity = ???

Don't be confused! Initial velocity cames as zero because the train starts from rest.

KnowlEdge required:

The first equation of motion is given by the mentioned formula,

• v = u + at

Where, a denotes acceleration, u denotes initial velocity, v denotes final velocity and t denotes time taken.

Required solution:

→ v = u + at

→ v = 0 + 5(5)

→ v = 0 + 25

→ v = 25 m/s

→ Final velocity = 25 m/s

• Therefore, the velocity of the train in 5 sec = 25 metre per second!

Answer 2

Answer:-

• Initial velocity=u=0m/s
• Acceleration=5/s^2
• Time=t=5s
• Final velocity=v=?

According to first equation of motion

$\boxed{\sf v=u+at}$

$\\ \sf\longmapsto v=0+5(5)$

$\\ \sf\longmapsto v=0+25$

$\\ \sf\longmapsto v=25m/s$