a train starts from rest and maintains uniform acceleration at a rate of 4 m/s^2. it the maintains uniform speed for 240 seconds. the train is uniformly retarded by applying brake to stop it in 48s. i) find maximum velocity reached , ii) the retardation in last 48 second, iii) the total distance travelled its urgent
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6
Answer:
1
=(
2
u+v
)t
=20×20=400m
S
2
=40×20=800m
S
3
=(
2
u+v
)t
=20×40=800m
Total displacement =2000 m
Total time taken =80 m
V=
80
2000
=25m/s
∴ Option C is correct.
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