a train starts from rest and moves with a constant acceleration 2 metre per second square for half a minute. the brakes then apply the train comes to rest in one minute. find (a)the total distance moved by the train(b) the maximum speed attained by the train and (c)the position of the train at half the maximum speed.
kirtiprasanjenpchfhd:
ask
actually I don't get the answers
and i think my process is right
yeah
show
it
how can i show
Okk then say in which part u have doubt
wait i am sending you that question
okk
Answers
Answered by
2
hope it helps
regards
Mohit Khairnar to
regards
Mohit Khairnar to
Attachments:
hye there is also more questions
u had solve only which i had already solved
Answered by
2
as you know that at first the train moves with speed 2m/s^2 for 30 sec so distance traveled in 30second=1/2* 2 *(30)^2= 900 meters
then at that time its speed=u+at=0+2*30=60 m/s...
as train comes to rest in 60 second the declaration will be 60/60=1m/s^2...
then at this time it will cover distance =60*60-1/2*1*60*60=1800meters
so total distance=900+1800=2700meters
and the highest speed is 60m/s
the position of train in half of its maximum speed is at time 30=2*t⇒t=15second
so position is=1/2*2*15*15=225meters
and other at timeof declaration at position 2250meters
then at that time its speed=u+at=0+2*30=60 m/s...
as train comes to rest in 60 second the declaration will be 60/60=1m/s^2...
then at this time it will cover distance =60*60-1/2*1*60*60=1800meters
so total distance=900+1800=2700meters
and the highest speed is 60m/s
the position of train in half of its maximum speed is at time 30=2*t⇒t=15second
so position is=1/2*2*15*15=225meters
and other at timeof declaration at position 2250meters
Similar questions