A train starts from rest. It moves through 1km in 100seconds with uniform acceleration. What will be its speed at the end of 100seconds?
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Answered by
31
s=ut+1/2at^2
u=0
1000m=1/2a×(100)^2
a=1000×2/100×100
=0.2m/s^2
from v=u+at
v=0.2 ×100=20m/s
u=0
1000m=1/2a×(100)^2
a=1000×2/100×100
=0.2m/s^2
from v=u+at
v=0.2 ×100=20m/s
Answered by
8
Answer:20ms-1
Explanation:sun rises from east thats why
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