A train starts from rest. It moves through 1km in 20 minutes with uniform acceleration. what will be its speed at the end of 20 seconds.
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Answered by
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Explanation:
S=ut+1/2at^2
u=0
1000m=1/2a×(100)^2
a=1000×2/100×100
=0.2m/s^2
from v=u+at
v=0.2 ×100=20m/s
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Answered by
1
1 km=1000m
speed= distance/ time
speed =1000/20=50
Speed=50 m or 0.0005 km
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