Question

A train starts from rest with an
acceleration of 0.5 ms 2. Find its
speed in kmh, when it has
moved through 100 m. (36 kmh")​

Answer 1

Given that,

Acceleration a=−0.5m/s 2

Speed v=90km/h=25m/s

Using equation of motion,  

v=u+at

Where,  

v = final velocity  

u = initial velocity  

a = acceleration  

t = time

Put the value into the equation  

Finally train will be rest so, final velocity ,v=0

0=25−0.5t

25=0.5t  

t=25/ 0.5  

t=50 sec

Again, using equation of motion,

S=ut+ 1/2at^2

Where, s = distance  

v = final velocity  

u = initial velocity  

a = acceleration

t = time

Put the value into the equation

Where S is distance travelled before stop

s=25×50− 1/2×0.5×(50) ^2

s=625 m

So, the train will go before it is brought to rest is 625 m.

Answer 2

Explanation:

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