Question

sina+cosa/sina-cosa + sina-cosa/sina+cosa=2/sin^2a-cos^2a=2/2sin^a-1

Answer 1

Step-by-step explanation:

sinA+cosA/sinA-cosA+sinA-cosA/sinA+cosA=(sinA+cosA)²+(sinA-cosA)²/sin²A-cos²A

=2(sin²A+cos²A)/sin²A-cos²A

=2/sin²A-cos²A

so, 2/sin²A-cos²A

=2/sin²A-1+sin²A

=2/2sin²A-1