Question

please answer the second question​

Answer 1

Here is your solution:-

${2}^{2x - 3} = {64}^{x} \\ \\ {2}^{2x - 3} = ( {2}^{6)x} \\ \\ {2}^{2x - 3} = {2}^{6x} \\ \\ comparing \: powers \: \\ \\ 2x - 3 = 6x \\ \\ - 3 = 6x - 2x \\ \\ - 3 = 4x \\ \\ x = \frac{ - 3}{4}$

Hope it helps.