a train starts from rest with an acceleration of 2m/s2. a man who is 9m behind the train runs with uniform speed and just manages to get into the train in 10 seconds. what is the speed of the man
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Answered by
29
Distance travelled by train in 10s
S = 0.5at^2
= 0.5 * 2 * 10^2
= 100 m
Speed = Total Distance / Time
= (100m + 9m) / 10s
= 10.9 m/s
Speed of man is 10.9 m/s (uniform).
S = 0.5at^2
= 0.5 * 2 * 10^2
= 100 m
Speed = Total Distance / Time
= (100m + 9m) / 10s
= 10.9 m/s
Speed of man is 10.9 m/s (uniform).
Answered by
14
Answer:
Distance travelled by train in 10s
S = 0.5at^2
= 0.5 * 2 * 10^2
= 100 m
Speed = Total Distance / Time
= (100m + 9m) / 10s
= 10.9 m/s
Speed of man is 10.9 m/s (uniform).
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