Question

a train starts from rest with an acceleration of 2m/s2. a man who is 9m behind the train runs with uniform speed and just manages to get into the train in 10 seconds. what is the speed of the man

Answer 1

Distance travelled by train in 10s
S = 0.5at^2
= 0.5 * 2 * 10^2
= 100 m

Speed = Total Distance / Time
= (100m + 9m) / 10s
= 10.9 m/s

Speed of man is 10.9 m/s (uniform).

Answer 2

Answer:

Distance travelled by train in 10s

S = 0.5at^2

= 0.5 * 2 * 10^2

= 100 m

Speed = Total Distance / Time

= (100m + 9m) / 10s

= 10.9 m/s

Speed of man is 10.9 m/s (uniform).