Question

I will also mark as brainliest only if I get answer step by step please guys it's really urgent (50 points)

Answer 1

use formula,
  relative density  = weight of iron in air/ weight of water displaced by iron
                              =( 155 gf)/(155 - 133) gf
                               = 155/22 = 7.045 ≈ 7.05

use formula, 
    the density of substance = RD × density of water 
    the density of iron = 7.05 ×1000 kg/m³ = 7.05 ×10³ Kg/m³
    volume of iron = mass / density = 155 g/7.05 ×10³ kg/m³
                             = 155/7.05 cm³ = 22 cm³ = 22 cc
density of iron piece in air = 7.05 g/cm³
density of iron piece in alcohol = 0.8 g/cm³
weight of alcohol displaced by iron = density of alcohol×mass of iron piece /density of iron piece = 0.8×155/7.05 = 17.58 g
hence weight of iron piece in alcohol = 155 - 17.58 = 137.42≈ 137.4 g

Answer 2

hope it helped u ..
plz mrk as brainliest answer