Question

A train starts from station A and reaches station D which is 150 km away. It has scheduled halts at station B and C for 5 minutes each. The distance between A and B is 50 km and C and D is 60 km. The train starts at 5 p.m. from A and reaches D at 8.30 p.m. What is its average speed in m/s

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Answer 1

Answer:

speed = total distance traveled/ Total time Taken

here total distance = 150km

total time taken = 3.5 h

avg speed = 150/3.5 = 42.8 km/hr

avg speed in m/s = 42.8 x 1000/ 60 * 60

= 11.88 m/s

Step-by-step explanation: