Question

A train starts from station A and reaches station D which is 150 km away. It has scheduled halts at station B and C for 5 minutes each.
The distance between A and B is 50 km and C and D is 60 km. The train starts at 5 p.m. from A and reaches D at 8.30 p.m. What is its average speed in m s?

(A) 11.88m s (B) 15.4m s (C) 8.41 m s (D) 5.83 m s.

m s means Meter per second.
please give answer in full method.​

Answer 1

Answer:

$speed \: = \frac{total \: distance \: travelled \: }{total \: time \: taken}$

Here total distance = 150km

Total time taken = 3. 5 h

Average speed =

$- > \frac{150}{3.5}$

$- > 42.8km \: per \: h$

Average speed in m/s =

$- > 42.8 \times \frac{1000}{60 \times 60}$

--> 11.88 m/ s

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