a train starts from station P with uniform acceleration a force of distance and there is goes to the uniform retardation 82 for some more distance to come to rest at the station to the distance between the station P and Q is 4 kilometre and the train takes 4 min to complete this journey it is acceleration are in kilometre /minute unit show that
1/a2+1/a2=2
Abhiraj30801:
82 nhi hoga
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First let us plot the graph with the data given.
Let the starting point be the origin in the speed - time graph.

(a) Uniform rate of acceleration = slope of AB
= (20−0) (m/s)/ [(200−0) s]
= 0.1 m/s2.
(b) Uniform retardation = − slope of CD
= − (0−20)(m/s) /[(800−700)s]
= 0.2 m/s2.
(c) Total distance covered before stopping = area under the curve ABCD
= area of ΔABE + area of rectangle BCFE + area of ΔCDF
= ½ x 200 x 20 + 500 x 20 + ½ x 100 x 20 m
= 2000 + 10000 + 1000 m
= 13,000 m = 13 km
(d) Average speed = Total distance covered/total time taken = 13000 m /(800 s)
= 16.25 m/s
Let the starting point be the origin in the speed - time graph.

(a) Uniform rate of acceleration = slope of AB
= (20−0) (m/s)/ [(200−0) s]
= 0.1 m/s2.
(b) Uniform retardation = − slope of CD
= − (0−20)(m/s) /[(800−700)s]
= 0.2 m/s2.
(c) Total distance covered before stopping = area under the curve ABCD
= area of ΔABE + area of rectangle BCFE + area of ΔCDF
= ½ x 200 x 20 + 500 x 20 + ½ x 100 x 20 m
= 2000 + 10000 + 1000 m
= 13,000 m = 13 km
(d) Average speed = Total distance covered/total time taken = 13000 m /(800 s)
= 16.25 m/s
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