Question

A train starts from the rest and attains a speed of 64 km per hour in 15 minutes. Calculate the acceleration and distance covered by the train.​

Answer 1

Answer:

Acceleration = a = 17.8/15×60 =0.0198 m/s

S = ut+1/2at^2 = 0+1/2 0.0198×810000 = 8.019 km answer...

Answer 2

Answer:

15min = 1/4hrs

velocity or speed= 64kmh , u=0

distance = sp×time

64×1/4

=16km

acceleration=( v-u)/t

(64-0)1/4

=16kmh^-2