Question

find the possible of a+b if 4a 3b is divisible by 11.​

Answer 1

Step-by-step explanation:

For the number

to be divisible by 11

the sum of digit at odd place that is a +b and the sum of digit at even place that is 4 +3= 7 and their difference = (a + b)- 7 should divisible by 11

⇒ (a+ b) -7 = 0

or (a+ b) -7 = 11