Physics, asked by bridzerazz71, 8 months ago

A train starts to move from rest.It is accelerated by 4 m/s².Calculate its velocity and time needed to travel 50 m distance.

Answers

Answered by Anonymous
29

Given :

  • Initial velocity of train (u) = 0m/s
  • Acceleration of train (a) = 4 m/s²
  • Distance travelled by train (s) = 50 m

To Find :

We have to find the final velocity and time taken by the train.

Explanation :

As, we have to find the time taken. So, firstly we will use second equation of the motion.

\large{\star{\underline{\boxed{\sf{s = ut + \dfrac{1}{2} at^2}}}}}

\rm{\dashrightarrow 50 = 0(t) + \dfrac{1}{\cancel{2}} \times \cancel{4} \times t^2} \\ \\ \rm{\dashrightarrow 50 = 0 + 2t^2} \\ \\ \rm{\dashrightarrow t^2 = \dfrac{\cancel{50}}{\cancel{2}}} \\ \\ \rm{\dashrightarrow t^2 = 25} \\ \\ \rm{\dashrightarrow t = \sqrt{25}} \\ \\ \rm{\dashrightarrow t = \pm 5}

As, time taken can't be negative. So, t = 5s

\large{\star{\underline{\boxed{\sf{t = 5 \: s}}}}}

\rule{200}{2}

Now,

We will use first equation of motion to find the final velocity.

\large{\star{\underline{\boxed{\sf{v = u + at}}}}}

\rm{\dashrightarrow v = 0 + 4(5)} \\ \\ \rm{\dashrightarrow v = 20}

\large{\star{\underline{\boxed{\sf{v = 20 \: ms^{-1}}}}}}

\rule{400}{4}

Answered by Anonymous
41

Given :

  • Initial velocity (u) = 0 m/s
  • Acceleration (a) = 4 m/s²
  • Distance Travelled (s) = 50 m

To Find :

  • Velocity and time needed to travel 50 m

Solution :

We are given that the car starts from rest. So, initial velocity (u) will be taken as 0 m/s. We've to find out velocity and time when the distance travelled is 50 m

Use 3rd equation of motion :

\implies \sf{v^2 \: - \: u^2 \: = \: 2as} \\ \\ \implies \sf{v^2 \: - \: 0^2 \: = \: 2 \: \times \: 4 \: \times \: 50} \\ \\ \implies \sf{v^2 \: = \: 8 \: \times \: 40} \\ \\ \implies \sf{v^2 \: = \: 400} \\ \\ \implies \sf{v \: = \: \sqrt{400}} \\ \\ \implies \sf{v \: = \: \pm 20}

As we know that velocity can't be taken as negative. So, we will take positive velocity.

\therefore Velocity when car travels 50m is 20 m/s

______________________________

Now, use 1st equation of motion :

\implies \sf{v \: = \: u \: + \: at} \\ \\ \implies \sf{20 \: - \: 0 \: = \: 4t} \\ \\ \implies \sf{4t \: = \: 20} \\ \\ \implies \sf{t \: = \: \dfrac{20}{4}} \\ \\ \implies \sf{t \: = \: 5}

\therefore Time when car travels 50m is 5 seconds.

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