A TRAIN TAKE 2 HRS TO REACH FROM STATION A TO STATION B WHICH IS AT A DISTANCE OF 200 KM FROM STATION A . IT TAKES 3 HRS TO RETURN JOURNEY . WHAT IS THE AVERAGE SPEED AND AVERAGE VELOCITY OF THE TRAIN
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Answered by
1
☺✌Total distance D=200+200=400 km
Average speed ∣V
avg
∣=
Total time
Total distance
∴ ∣V
avg
∣=
2+3
400
=80 km/h
Displacement S=0
Average velocity V
avg
=
Total time
Total displacement
∴ V
avg
=
2+3
0
=0 km/h✌☺
Answered by
1
Explanation:
Average speed = total distance/total time
(It includes both the went and the return of the train)
Average speed = 200+200/2+3
Speed =400/5
Speed= 80m.
Velocity \= displacement /time.
( though it comes back to it's original position it do not have distance between them)
= 0
Velocity =0.
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