Question

A train takes 2 h to reach station B from station A, 8
distance between the two stations is 200 km. Fin
then 3 h to return from station B to station A.
(i) the average speed, (ii) the average velocity of the train

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Answer 1

Answer:

Total distance D=200+200=400 km

Average speed ∣V

avg

∣=

Total time

Total distance

∴ ∣V

avg

∣=

2+3

400

=80 km/h

Displacement S=0

Average velocity V

avg

=

Total time

Total displacement

∴ V

avg

=

2+3

0

=0 km/h

Answer 2

Answer:

Hi friend,

Average speed = total distance/total time

(It includes both the went and the return of the train)

Average speed = 200+200/2+3

Speed =400/5

Speed= 80m.

Velocity \= displacement /time.

( though it comes back to it's original position it do not have distance between them)

:- =0

Velocity =0.

Hope this helped you a little!!!

Explanation: