.A train takes 3 h to reach from station A to station B at a distance of 400 km and 5 h in its return journey. Find the average speed in ( i ) km/h ( ii ) m/s.
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Answer:
Total distance D=200+200=400 km
Average speed ∣V
avg
∣=
Total time
Total distance
∴ ∣V
avg
∣=
2+3
400
=80 km/h
Displacement S=0
Average velocity V
avg
=
Total time
Total displacement
∴ V
avg
=
2+3
0
=0 km/h
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Given :
Distance between the two stations A and B = 400 km
Total distance travelled from A to B and then from B to A
d = 400 km + 400 km = 800 km
Total time of journey t = 3 h + 5 h = 8 h
(1) Average speed=800km/8h
=100km/h−1
(2) Average speed=100×1000/3600
=27.7m/s
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