Question

a train takes 3 hours to reach from station A to station B and then 5 hours to return from station B to station A the distance between the two stations is 400 km calculate the average speed of the train​

Answer 1

Answer:

100 km/h

Explanation:

As per the provided information in the given question, we have :

• Time taken by the train to cover the distance from A to B $\sf (t_1)$ = 3 hrs
• Time taken by the train to cover the distance from B to A $\sf (t_2)$= 5 hrs
• Distance between two stations = 400 km

We are asked to calculate the average speed of the train.

We shall be using average speed formula in order to calculate the average speed of the train.

$\boxed{\sf {Speed_{(avg)} = \dfrac{Total \; s}{Total \; t} }}$

• Total s denotes total distance
• Total t denotes total time

★ Calculating total distance travelled :

Since, the train covers from station A to B and ten returns back, that means total distance covered by it ,

→ Total distance covered = Distance from station A to B + Distance from B to A

→ Total distance covered = 400 km + 400 km

→ Total distance covered = 800 km__(Eq. 1)

★ Calculating total time :

→ Total time = Time taken by train to cover the distance from town A to town B + Time taken by train to cover the distance from town B to town A

→ Total time = $\sf t_1 + t_2$

→ Total time = 3 hrs + 5 hrs

→ Total time = 8 hrs__(Eq. 2)

Now, substituting the value of total time taken and total distance travelled from equation 1 and equation 2 in the formula to calculate average speed.

$\longmapsto \boxed{\sf {Speed_{(avg)} = \dfrac{Total \; s}{Total \; t} }}$

Substituting the values.

$\longrightarrow \sf {Speed_{(avg)} = \dfrac{800 }{8} \; kmh^{-1} }$

Dividing 800 by 8. We get,

$\longrightarrow\underline{\boxed{ \sf {Speed_{(avg)} = 100 \; kmh^{-1} }} } \; \bigstar$

$\therefore$ Average speed of the train 100 km/h.