a train travel 20 km at uniform speed of 60 km /h and the next 20 km at the inform speed of 80 km /h. calculate the average speed.
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CASE 1:
DISTANCE(D1) = 20 KM
SPEED(S1) = 60 KMPH
TIME(T1) = DISTANCE/SPEED = D1/S1 = 20/60 = 1/3 HOURS
NOW, CASE 2:
DIATANCE(D2) = 20 KM
SPEED(S2) = 80 KMPH
TIME(T2) = DISTANCE/TIME = D2/S2 = 20/80 = 1/4 HOURS
NOW,
AVERAGE SPEED = TOTAL DISTANCE / TOTAL TIME
= (D1 + D2)/(T1 + T2)
= (20 + 20)/{1/3 + 1/4}
= (40)/{(4+3)/12}
= 40/7/12
= 40 * 12/7
= 68.57 KMPH
HENCE, THE AVERAGE SPEED FOR THE ENTIRE JOURNEY IS
68.57 KMPH
DISTANCE(D1) = 20 KM
SPEED(S1) = 60 KMPH
TIME(T1) = DISTANCE/SPEED = D1/S1 = 20/60 = 1/3 HOURS
NOW, CASE 2:
DIATANCE(D2) = 20 KM
SPEED(S2) = 80 KMPH
TIME(T2) = DISTANCE/TIME = D2/S2 = 20/80 = 1/4 HOURS
NOW,
AVERAGE SPEED = TOTAL DISTANCE / TOTAL TIME
= (D1 + D2)/(T1 + T2)
= (20 + 20)/{1/3 + 1/4}
= (40)/{(4+3)/12}
= 40/7/12
= 40 * 12/7
= 68.57 KMPH
HENCE, THE AVERAGE SPEED FOR THE ENTIRE JOURNEY IS
68.57 KMPH
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