A train travel between two stations A and B, a distance of 108km in 45 minutes. It passes through a station C, 40 minutes after leaving A. what is the distance between B and C?
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Answered by
0
s=d/t
therefore speed of train from a to b
s=108/45×60
s=2.4×60
s=144km/h
distance between b and c
144×40/60
72×3
216km
therefore speed of train from a to b
s=108/45×60
s=2.4×60
s=144km/h
distance between b and c
144×40/60
72×3
216km
shreyashpandey2:
Wrg
Answered by
5
Time taken for traveling A and B=45 minutes
Distance between A and B = 108 km
Time taken for reaching B from C = 45-40=5min
By direct proportion
x1/y1=x2/y2
108/45=x/5
108/45×5=x
12=x
So,distance between B and C is 12 km
Distance between A and B = 108 km
Time taken for reaching B from C = 45-40=5min
By direct proportion
x1/y1=x2/y2
108/45=x/5
108/45×5=x
12=x
So,distance between B and C is 12 km
Is this correct.
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