a train traveling 90 km/h crosses a stationary goods train 200m long in the same direction in 15 s. in how much time will it cross a man moving in the opposite direction at 5m/s
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Step-by-step explanation:
speed of train = 90km/h or 90×1000/3600
= 25m/s
total distance covered by train while crossing goods train will be = sum of length of both trains
= 200+length of train
distance = speed×time
so,
200+ length of train=25×15
=375m
,length of train =375-200
=175m
when train will cross a man moving with speed of 5m/s in opposite direction
so , relative speed = 25m/s +5m/s
= 30m/s
time taken = distance/ relative speed
= 175/30
=5.83 sec
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