Question

A train traveling at a uniform speed passes by a platform 220 m long in 30 s and another platform 325 m long in 39 s Find.
(i) the length of train and the speed of train
I need a answer with process if you have no process don't answer otherwise your answer will be reported​

Answer 1

Given s =t+ 220/30 ••••••• (1)

and s= t + 325/39 ••••••• (2)

on solving (1) and (2), we get

39(t + 220) = 30(t + 325)

39t + 8580 = 30t + 9750

9t = 1170

t = 130 metres

Substitute in (1), we get

Speed = 130 + 220/30

= 350/30 =

= 11.66 m/sec

On converting it to km/hr, we get

S = 3600 * 11.66/1000

= 41.9

= ~42

brainliest please...

Answer 2

Required Answer ⤵️

Given:-

Speed,s = t + 220/30 --------(i)

Speed,s = t + 325/39 --------(ii)

From (i) and (ii),

we will get:-

$t + \frac{220}{30} = t + \frac{325}{39}$

After cross multiplication:-

39(t + 220) = 30(t + 325)

39t + 8580 = 30t + 9750

9t = 1170

t = 130 metres

Substitute in (i), we get

Speed,s = 130 + 220/30

= 350/30

= 11.66 m/sec

we will convert it to km/hr, we get

Speed,s = 3600 x 11.66/1000

= 41.9

= ~42 Ans

Hope it helps you