a train travelled a certaon distance at a uniform speed. If the train had been 7km/hr faster, it would have taken 14 hours less than the scheduled time.If the train were slower by 3km/hr then it would have taken 10 hours more than the scheduled time.Find the distance covered by the train?
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Step-by-step explanatiLet t be the usual time taken by the train to cover the distance
Let d be the distance, s be the usual speed
Usual time taken => d/s = t => d=ts
d/(s+6) = t-4
ts/(s+6) = t-4
ts = ts+6t-4s-24
6t - 4s - 24 = 0 --> (1)
d/(s-6) = t+6
ts = ts-6t+6s-36
-6t + 6s - 36=0 --->(2)
Solving (1) nd (2), v get
s = 30 km/h
t = 24 hrs
d = t * s
d = 30 * 24 = 720 km
Ans : 720 km
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