evaluate cossquare67-sinsquare23
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akshatkhurania:
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the A should be of sin in this case
what??
i didnt understand
i meant is sin23=cos(90-67)
you can do both it doesn't matter
or sin23=cos(90-23)
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Hey... I think this can be ur answer dear!!
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Cos²67 - sin²23
= cos² (90-23) - sin² 23
= sin² 23 - sin²23
=0
SO, the value is 0...
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Hope it helps you dear ☺️☺️☺️
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