a train travelles 20km at a uniform speed of 60km/hr and next 20km at a uniform of 80km /hr calculate its average speed. with solution plz
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The train travelled 20km with speed of 60kmph in time 20/60 = 1/3 hours
The train travelled next 20km with speed of 80kmph in time 20/80 = 1/4 hours
The average speed = total distance/ total time
= (20+20)/(1/3+1/4)
= 40/(7/12)
= 480/7 kmph
The train travelled next 20km with speed of 80kmph in time 20/80 = 1/4 hours
The average speed = total distance/ total time
= (20+20)/(1/3+1/4)
= 40/(7/12)
= 480/7 kmph
Hannah1301:
I'm not telling u are wrong.. U're absolutely correct
But we can also use that
n?
N is the no. Of digits... Like in this case we have been given 2 speeds so we will substitute 2 for the value of n
2× 20× 60/80?
like this?
Got It??
yup
thx
Welcome
Answered by
2
Here is the technique
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but that wont be true of the distances travelled will not be equal, isnt it?
say he travels 20km first the 50 km next
you will have to solve this using the concept then!
Yes this is just only if the distance intervals are same
ok ..
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