Question

A train travelling at 20 m s−1 accelerates at 0.5 m s−2 for 30 s. How far will it travel in this time?

Answer 1

Answer:

Given

initial velocity , u = 20

acceleration = +0.5

time = 30 s

Since

$s = ut + \frac{1}{2} a {t}^{2} \\ \\ s = 20(30) + \frac{1}{2} \times \frac{1}{2} \times {30}^{2} \: \\ \\ s = 600 + 225 \\ \\ s = 825 \: m$

Answer 2

$\huge{\bf{ \red{\fbox{ \color{blue}{Answer :-}}}}}$

Given :-

Initial Velocity(u) = 20 m/s

Acceleration = 0.5 m/s²

Time = 30s

To Find :-

Distance covered by the train

Solution :-

We know that,

$\huge{\boxed{\blue{\sf{s = ut + \frac{1}{2}at^2}}}}$

__________[Put Values]

s = 20(30) + (0.5 * 30²) / 2

s = 600 + 450 /2

s = 600 + 225

s = 825 m

$\huge{\bf{ \red{\fbox{ \color{blue}{Distance(s) \: = \: 825 \: m}}}}}$