Question

A train travelling at 20 m s^-1 accelerates at 0.5m s ^-2 for 30s .how far will it travel in this time

Answer 1

Answer :-

Given :-

▪️Initial velocity = 20 m/s

▪️Acceleration = 0.5 m/s² = 1/2 m/s²

▪️Time = 30 sec

Now we have to find out the distance travelled in 30 sec during the period of Acceleration.

As we have

S = ut + 1/2 at²

→ S = 20(30) + 1/2 × 1/2 × 30²

→ S = 600 + 1/4 × 900

→ S = 600 + 225

→ S = 825 m

So train will travel 825 m

Answer 2

Answer:

Speed = u = 20 m/s

Acceleration = a = 0.5 m/s^2

Time = t = 30s

S = ut + (at^2)/2

= 20×30 + (0.5×30×30)/2

= 600 + 225 = 825 m

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