Question

An oxide of metal has 20% oxygen,the equivalent weight of metal oxide is?

Answer 1

Let the total amount of oxide be 100

∴ mass of oxygen is 20

∴ mass of element is (100-20)=80

∴equivalent mass of element = mass of element mass of oxygen mass of element mass of oxygen×8×8

=8020=8020×8×8

=32=32.

Equivalent weight is that which combines with 8 parts by weight of oxygen.

as per data Oxygen 20%: metal 80 %

Thus eq wt of metal =32.

depending upon at wt, one has to find valency of metal, formula of metal sulphate & hence its eqivalent wt.

Answer 2

Answer :

Equivalent weight of metal oxide = 52 grams

Step-by-step explanation :

Given,

20% of oxygen in oxide.

So, in 100 grams,

If 20 grams of oxygen in metal oxide, the weight of metal will be :

=> 100 - 20

=> 80 grams of metal.

Then,

.°. Mass of metal / Mass of oxygen = Equivalent weight of metal / Equivalent weight of oxygen

=> 80 g / 20 g = x / 8

=> 80 × 8 / 20 = x

.°. x = 32 grams

So, the total weight of metal oxide = weight of metal + weight of oxygen = 32 grams + 20 grams = 52 grams.