Question

a train travelling at 20 m/s accelerates at 0.5m/s square for thirty seconds. how far will it travel in this time?

Answer 1

HOLA!!

________

HERE YOUR ANSWER IS

GIVEN:

Intial velocity (u) = 20ms^-1

9Acceleration (a) = 0.5ms^-2

time (t) = 30

SOLUTION:

We can solve this by kinematical equation

s = ut+ 1/2 at^2

= 20m/s + 1/2 (0.5 )(30)^2

= 20 + 1/2 (0.5)(900)

= 20 + (0.5)(450)

= 20 + (5/10)(450)

= 20 + (5)(45)

=20 + (225)

s = 245m

ANSWER : Distance = 245m