a train travelling at 20 m/s accelerates at 0.5m/s square for thirty seconds. how far will it travel in this time?
Answers
Answered by
1
HOLA!!
________
HERE YOUR ANSWER IS
GIVEN:
Intial velocity (u) = 20ms^-1
9Acceleration (a) = 0.5ms^-2
time (t) = 30
SOLUTION:
We can solve this by kinematical equation
s = ut+ 1/2 at^2
= 20m/s + 1/2 (0.5 )(30)^2
= 20 + 1/2 (0.5)(900)
= 20 + (0.5)(450)
= 20 + (5/10)(450)
= 20 + (5)(45)
=20 + (225)
s = 245m
ANSWER : Distance = 245m
________
HERE YOUR ANSWER IS
GIVEN:
Intial velocity (u) = 20ms^-1
9Acceleration (a) = 0.5ms^-2
time (t) = 30
SOLUTION:
We can solve this by kinematical equation
s = ut+ 1/2 at^2
= 20m/s + 1/2 (0.5 )(30)^2
= 20 + 1/2 (0.5)(900)
= 20 + (0.5)(450)
= 20 + (5/10)(450)
= 20 + (5)(45)
=20 + (225)
s = 245m
ANSWER : Distance = 245m
hyunxu:
give me the ans pls..
Similar questions
Math,
6 months ago
Computer Science,
1 year ago
Math,
1 year ago
Psychology,
1 year ago
Math,
1 year ago