Question

a train travelling at 20 M s accelerates at 0.5ms for 30s.howfar will it travel in this time

Answer 1

by 3rd equation of motion - S= ut+1/2*at^2

u=20. t=30s, Acceleration = 0.5

putting values s=20(30)+1/2(0.5)(30)^2

= s= 600+1/2+450

= s=600+225

= 825 m

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