Question

A train travelling at 20m/s accelerates at0.5m/s^2 for 30 secounds how far with it travel with this lin

Answer 1

ʜᴇʟʟᴏ ᴍᴀᴛᴇ!

Here, initial velocity ( u ) = 20 m/s

acceleration ( a ) = 0.5 m/s²

time ( t ) = 30 s

v = u + at

v = 20 + (0.5)(30)

v = 20 + 15

v = 35 m/s

Now,

v² - u² = 2as

(35)² - (20)² = 2(0.5)(s)

( 35 + 20 )( 35 - 20 ) = s

55*15 = s

825 m = s ( distance )

Hope it helps