Question

A train travelling at 30 ms -1. accelerates at 0.5ms-1 for 30s​

Answer 1

Answer:

1125m and 1.125km

Explanation:

according to second law of motion

s=ut+1/2at

substitution value

s=30×30+1/2×(0.5)×30square

s=90+1/2×(0.5)×900

s=900+0.5×450

s=900+225

s=1125m

hence the distance covered by train at given time interval is 1125m or 1.125km