Question

a train travelling at a speed of 120 km/hr. Brakes are applied so as to produce a uniform acceleration of - 0.5m/s^-2. How far the train will go before it is brought to rest​

Answer 1

Answer:

Given,

u=108km/h=

60×60

108×1000

=30m/s

a=−1m/s

2

v=0m/s

From 3rd equation of motion,

2as=v

2

−u

2

−2×1×s=0

2

−30×30

s=

−2×1

−30×30

s=450m