Question

a train travelling at a speed of 90 km per hour. the brakes are applied so as to produce a uniform acceleration of minus 0.5 m/s² find how far does the train go before it is brought to rest.

Answer 1

intial speed of train, u =90km per hour = 90×5/18 = 25 m per senond

final speed, u = 0

Acceleration, a = - 0.5 m per seconds

we know that, v^2-u^2 = 2as

(0)^2 - (25)^2 = 2 × (-0.5) s

- 625 = -1s

s = - 625 / -1

s = 625 m

Answer 2

Answer:

625m

Explanation:

v= u+at

v= 0

0= 25- 0.5 t

25= 0.5t

t= 25/0.5

t= 50sec

s= ut + 1/2 at^2

s= 25×50 -1/2 × 0.5× 50^2

s= 625m

hence, the answer is 625m

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