a train travelling at a uniform speed for 360 km would have taken 48 minutes less to travel the same distance if its speed was 5 km per hour more . find the original speed of the train
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45 km/hr
take speed as xkm/h
therfore eq. is 360/x -360/x+5=48/60 (time has to be converted from 48 min to 48/60 hr)
on solving we get, 1800/ Xsq. + 5=4/5 =Xsq. +5X-2250=0
so x=45 or x=-50(dicarded) hence speed of train=45km/hr
take speed as xkm/h
therfore eq. is 360/x -360/x+5=48/60 (time has to be converted from 48 min to 48/60 hr)
on solving we get, 1800/ Xsq. + 5=4/5 =Xsq. +5X-2250=0
so x=45 or x=-50(dicarded) hence speed of train=45km/hr
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