Question

A train travelling at a uniform speed for 360 km would have taken 48 min less to travel the same distance if its speed were 5 km/h more. Find the original speed of the train.​

Answer 1

Answer:

x = 45

Step-by-step explanation:

$Let x= Original \: Speed</p><p></p><p></p><p> \: we \: know \: that \:  speed \: distance=time</p><p></p><p></p><p>So \: as \: per \: the \: question \: the \: following \: equation \: can \: be \: formed</p><p></p><p>x \: 360 \: − \: x+ \: 5360=6048    \: [1 hour \: = 60 \: minutes]</p><p></p><p></p><p>⇒x1−x+ \: 51=6048⋅ \\ 3601 </p><p></p><p>⇒x2+5x5= \: 4501</p><p></p><p>⇒x2+5x−2250=0</p><p></p><p>⇒x2− \: 45x+ \: 50x− \: 2250=0</p><p></p><p>⇒x(x−45)+50(x−45)=0</p><p></p><p>⇒(x−45)(x+50)=0</p><p></p><p>x=45,−50</p><p></p><p> \\ As \: the \: speed \: can't \: be \: negative \: so,</p><p></p><p></p><p>x=45</p><p></p><p>$

The above answer is 45 and mark me brainliest please

Answer 2

Answer:

let x = original speed

we knows that distance/speed = time

so as per the question the following equation can be formed 360/x - 360/x+5 = 48/60

1/x - 1/x+5, = 48/60 1/360

5/x square + 5x = 1/450

x square + 5x - 2250=0

x square - 45x + 50x- 2250=0

x(x-45) + 50(x-45)=0

(x- 45) ( x+50)=0

x = 45,- 50

as the speed can't be negative so

x=45 answer